# Sum square difference # The sum of the squares of the first ten natural numbers is, # 12 + 22 + ... + 102 = 385 # The square of the sum of the first ten natural numbers is, # (1 + 2 + ... + 10)2 = 552 = 3025 # Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640. # Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum. x = raw_input('Enter your choice for n natural number?: ') y = int(x) squaresum = (y*(y+1)*(2*y+1))/6 sum = (y*(y+1)/2)*(y*(y+1)/2) print sum - squaresum

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